Feeding a Bar Reading into an SI Pressure-Drop Calculation
Process datasheets talk in bar. Hydraulic calculations do not. The moment you write down Darcy–Weisbach, a velocity head or a Bernoulli term with density in kg/m³ and velocity in m/s, the answer lands in pascals — newtons per square metre — and every allowance borrowed from a vendor sheet has to arrive in the same unit before it can be added up.
The Four Terms That Make Up a Loop Total
Friction down the straight run
Velocity head at fittings
Equipment allowances from vendors
Static elevation change
From Vendor Sheet to Calculation Column
The routine below is what a hydraulic check sheet actually needs — one consistent unit down the whole column, then a single total.
Enter the allowance exactly as the datasheet prints it
Put 0.35, 0.5 or 0,7 into the bar field — a comma reads the same as a dot here, and any spaces pasted in with the number are dropped. The pascal value appears while you type, with thousands spaced out so 70 000 cannot be mistaken for 7 000.
Line the equipment items up beside the friction terms
Once strainer, exchanger and control valve are all in pascals they add straight onto the ρgh and ½ρv² results, and the pump differential falls out of one subtraction rather than three unit changes.
Move the plain figure into the sheet
Each field has a copy button that hands over the number on its own — no unit, no digit grouping — which is what a spreadsheet cell or a solver input box will accept. Ctrl + C from inside a field does the same thing.
Turn the solver output back into gauge language
Simulation results come back in pascals; the operator wants bar. The swap button (↔) runs Pa → bar, a multiplier of 0.00001, so 45 000 Pa reports as 0.45 bar on the line list.
Pressure Drop Budget of a Typical Process Loop
Order-of-magnitude allowances used when a liquid circuit is first sized, shown as the pascal value the calculation carries and the bar figure a datasheet prints. Water-like fluid at moderate velocity; a firm selection replaces every line with vendor data.
| Component or term | Basis | Δp (Pa) | Δp (bar) |
|---|---|---|---|
| Long-radius 90° elbow | K = 0.3, water at 2 m/s | 599 Pa | 0.00599 bar |
| One velocity head | ½ρv², water at 2 m/s | 1 996 Pa | 0.01996 bar |
| Basket strainer, clean element | Typical start-of-run allowance | 10 000 Pa | 0.1 bar |
| Orifice plate flow element | Permanent loss, moderate β ratio | 25 000 Pa | 0.25 bar |
| Gasketed plate exchanger | Common HVAC-duty specification | 30 000 Pa | 0.3 bar |
| 100 m of DN100 line | f = 0.02, water at 2 m/s | 39 920 Pa | 0.3992 bar |
| Shell-and-tube exchanger, tube side | Usual design ceiling | 50 000 Pa | 0.5 bar |
| Control valve at design flow | Sized to hold authority over the loop | 70 000 Pa | 0.7 bar |
Read down the pascal column and the shape of the problem appears: a single elbow is noise beside the control valve, and the valve alone can outweigh a hundred metres of pipe. That is the argument for sizing the valve last, once every fixed loss is known.
What This Page Does for Hydraulic Work
Flip the direction for a datasheet check
One press of the swap control turns the page into Pa → bar, the direction wanted when a solver reports 39 920 Pa and the line list expects 0.3992 bar.
Line-list units share one dropdown
Both sides carry all 26 pressure units in eight families, so mmH₂O on an old vent calculation or N/mm² on a nozzle rating can be pulled into the same comparison.
Small terms survive the conversion
Output carries up to eight decimals and drops into scientific notation below a millionth, so a sliver of duct loss does not round itself away to zero.
Figures ready for the check sheet
Copying takes the bare digits, so a pasted value lands in a formula cell as a number instead of arriving as text with a unit stuck to the end.
Questions from the Hydraulic Calculation Sheet
Why do pipe pressure-drop equations return pascals rather than bar?
Because the pascal is what falls out of the algebra. Feed kg/m³, m/s and metres into Darcy–Weisbach and the units reduce to kg·m⁻¹·s⁻², which is the newton per square metre. Bar is a convenience unit bolted on afterwards for gauges and datasheets, worth exactly 100 000 of them.
How much is one velocity head worth in a normal process line?
For water near 1 000 kg/m³, ½ρv² gives 1 996 Pa at 2 m/s and 4 491 Pa at 3 m/s — about 0.02 bar and 0.045 bar. The term scales with the square of velocity, so pushing a line from 2 to 3 m/s more than doubles every K-factor loss on it while the friction term climbs steeply alongside.
A gauge shows 4 bar g — what value belongs in an absolute-pressure term?
Convert first, then add ambient. 4 bar becomes 400 000 Pa, and a sea-level barometric pressure of about 101 325 Pa brings the absolute value to roughly 501 325 Pa. Vapour-pressure margins, gas density and compressible-flow work all need that absolute figure; friction losses do not care, because they are differences.
Static, dynamic or total — which pressure does a line-mounted transmitter see?
A tapping flush with the pipe wall senses static pressure, because the fluid is never brought to rest against it. Total pressure is static plus the ½ρv² dynamic term and needs a probe facing into the flow. In a liquid line at 2 m/s that difference is about 2 000 Pa — invisible on a 0–10 bar dial, yet decisive in a Bernoulli balance written between two different diameters.
Why does one vendor quote 0.5 bar, another 50 kPa and a third 5.1 m of water?
All three are the same 50 000 Pa written in the dialect of a different trade — process, SI-strict and pump-curve respectively. A metre of water column stands at 9 806.65 Pa, so 50 000 Pa is 5.0986 m. Keeping pascals as the working unit inside the calculation and translating only at the boundaries stops one line item being counted twice in two dialects.
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